x^2+10x=49

Solution for x^2+10x=49 equation:

x^2+10x=49

We move all terms to the left:

x^2+10x-(49)=0

a = 1; b = 10; c = -49;
Δ = b2-4ac
Δ = 102-4·1·(-49)
Δ = 296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{296}=\sqrt{4*74}=\sqrt{4}*\sqrt{74}=2\sqrt{74}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{74}}{2*1}=\frac{-10-2\sqrt{74}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{74}}{2*1}=\frac{-10+2\sqrt{74}}{2}
$